52. The two coils wound on a common core. The inductance of the first coil L1 = 0,16 TR, the second - L2 = 1 TR, the second coil resistance R2 = 400 ohms. Determine power current I2 to the second coil, when the current of 0.4 A, the current in the first coil is off for 0,002 s.
Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
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