143. Solving a chemistry problem

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6.34. Using the benzene adsorption isotherm, determine the specific surface area of the adsorbent (T = 293 K, S0 = 49 * 10–20 m2):
P / Ps 0.08 0.16 0.25 0.35 0.45 0.52
A, mol / kg 0.46 0.61 0.76 0.89 1.09 1.26

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