Consider the possibility of spreading an aqueous solution of valeric acid over the surface of mercury, based on the values of surface tension: σр-р – air = 25 mJ/m2; σmercury-air= 475 mJ/m2; σmercury - solution = 329 mJ/m2. If the solution spreads over the surface of mercury, how will the polar groups of valeric acid orient themselves: towards water or towards mercury? Explain why.
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