131.Solving a chemistry problem
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6.13 Using the adsorption isotherm, determine the specific surface area of the adsorbent (T = 239 K, S0 = 49.10-20 m2):
P/PS 0.05 0.12 0.20 0.30 0.40 0.50
A*105, kmol/kg 3.1 5.98 8.0 11.0 13.6 17.7
P/PS 0.05 0.12 0.20 0.30 0.40 0.50
A*105, kmol/kg 3.1 5.98 8.0 11.0 13.6 17.7
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